In this case, the method in a subclass will be overloading the method from the superclass instead of overriding it. If it is unintended, it may result in latent bugs.
Example:
public class Foo {
void foo(int x) {}
}
public class Bar extends Foo {
void foo(Number x) {} // Method 'foo()' overloads a compatible method of a superclass,
// when overriding might have been intended
}
Use the option to choose whether the inspection should also report cases where parameter types are not compatible.